Python Institute JSA-41-01 Practice Exams
Last updated on Oct 22,2026- Exam Code: JSA-41-01
- Exam Name: JSA - Certified Associate JavaScript Programmer
- Certification Provider: Python Institute
- Latest update: Oct 22,2026
Question #209
console.log(myCar);
What will be the output of console.log(myCar)?
- A . { make: ‘Toyota’, model: ‘Corolla’, year: undefined }
- B . { year: 2020 }
- C . { make: ‘Toyota’, model: ‘Corolla’ }
- D . { make: ‘Toyota’, model: ‘Corolla’, year: 2020 }
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #212
console.log(mergedPreferences);
- A . const mergedPreferences = { …preferences2, …preferences1 };
- B . const mergedPreferences = Object.assign(preferences1, preferences2);
- C . const mergedPreferences = preferences1.concat(preferences2);
- D . const mergedPreferences = { …preferences1, …preferences2 };
Correct Answer: D
Question #220
console.log(trimmedSentence);
What will be the output?
- A . "JavaScript…"
- B . "JavaScript"
- C . "JavaScript….."
- D . " JavaScript "
Correct Answer: C